6(a+1)=8[a-(3-a)]

Solution for 6(a+1)=8[a-(3-a)] equation:

Simplifying
6(a + 1) = 8[a + -1(3 + -1a)]

Reorder the terms:
6(1 + a) = 8[a + -1(3 + -1a)]
(1 * 6 + a * 6) = 8[a + -1(3 + -1a)]
(6 + 6a) = 8[a + -1(3 + -1a)]
6 + 6a = 8[a + (3 * -1 + -1a * -1)]
6 + 6a = 8[a + (-3 + 1a)]

Reorder the terms:
6 + 6a = 8[-3 + a + 1a]

Combine like terms: a + 1a = 2a
6 + 6a = 8[-3 + 2a]
6 + 6a = [-3 * 8 + 2a * 8]
6 + 6a = [-24 + 16a]

Solving
6 + 6a = -24 + 16a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-16a' to each side of the equation.
6 + 6a + -16a = -24 + 16a + -16a

Combine like terms: 6a + -16a = -10a
6 + -10a = -24 + 16a + -16a

Combine like terms: 16a + -16a = 0
6 + -10a = -24 + 0
6 + -10a = -24

Add '-6' to each side of the equation.
6 + -6 + -10a = -24 + -6

Combine like terms: 6 + -6 = 0
0 + -10a = -24 + -6
-10a = -24 + -6

Combine like terms: -24 + -6 = -30
-10a = -30

Divide each side by '-10'.
a = 3

Simplifying
a = 3